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x^2=62/36
We move all terms to the left:
x^2-(62/36)=0
We add all the numbers together, and all the variables
x^2-(+62/36)=0
We get rid of parentheses
x^2-62/36=0
We multiply all the terms by the denominator
x^2*36-62=0
Wy multiply elements
36x^2-62=0
a = 36; b = 0; c = -62;
Δ = b2-4ac
Δ = 02-4·36·(-62)
Δ = 8928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8928}=\sqrt{144*62}=\sqrt{144}*\sqrt{62}=12\sqrt{62}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{62}}{2*36}=\frac{0-12\sqrt{62}}{72} =-\frac{12\sqrt{62}}{72} =-\frac{\sqrt{62}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{62}}{2*36}=\frac{0+12\sqrt{62}}{72} =\frac{12\sqrt{62}}{72} =\frac{\sqrt{62}}{6} $
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